Find the interval of convergence of the series.
-$$\sum _ { n = 0 } ^ { \infty } \frac { ( x - 2 ) ^ { n } } { n ^ { 4 } 2 ^ { n } }$$
A) $1 \leq x \leq 3$
B) $- 4

Question

Find the interval of convergence of the series.
-$$\sum _ { n = 0 } ^ { \infty } \frac { ( x - 2 ) ^ { n } } { n ^ { 4 } 2 ^ { n } }$$
A) $1 \leq x \leq 3$
B) $- 4 < x < 4$
C) $x < 4$
D) $0 \leq x \leq 4$

Quizplus · Accepted Answer

The Answer of Find the interval of convergence of the series.
-$$\sum _ { n = 0 } ^ { \infty } \frac { ( x - 2 ) ^ { n } } { n ^ { 4 } 2 ^ { n } }$$
A) $1 \leq x \leq 3$
B) $- 4 < x < 4$
C) $x < 4$
D) $0 \leq x \leq 4$

Find the Interval of Convergence of the Series ∑n=0∞(x−2)nn42n\sum _ { n = 0 } ^ { \infty } \frac { ( x - 2 ) ^ { n } } { n ^ { 4 } 2 ^ { n } }n=0∑∞​n42n(x−2)n​

Find the Interval of Convergence of the Series $\sum _ { n = 0 } ^ { \infty } \frac { ( x - 2 ) ^ { n } } { n ^ { 4 } 2 ^ { n } }$