Solve.
-$$3 x ^ { 2 } + 19 x - 40$$
A) $( 3 x + 8 ) ( x - 5 )$
B) $( x - 8 ) ( 3 x - 5 )$
C) $( 3 x - 45 ) ( 3 x - 5 )$
D) $( x + 8 ) ( 3 x - 5 )$

Name: Solve. -\[3 x ^ { 2 } + 19 x - 40\] A) $( 3 x + 8 ) ( x - 5 )$ B) $( x - 8 ) ( 3 x - 5 )$ C) $( 3 x - 45 ) ( 3 x - 5 )$ D) $( x + 8 ) ( 3 x - 5 )$
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Question

Quizplus · Accepted Answer

The quadratic $3x^2 + 19x - 40$ factors into $(x + 8)(3x - 5)$ because expanding this product gives the original quadratic.

Solve - 3x2+19x−403 x ^ { 2 } + 19 x - 403x2+19x−40

Solve
- $3 x ^ { 2 } + 19 x - 40$