Solve.
-$3 x ^ { 2 } - 21 x + 36$
A) $( 3 x - 9 ) ( x - 4 )$
B) Prime
C) $3 ( x - 3 ) ( x - 4 )$
D) $3 ( x - 12 ) ( x + 1 )$

Question

Quizplus · Accepted Answer

The correct factorization of $3x^2 - 21x + 36$ is found by first factoring out the greatest common factor, which is 3, resulting in $3(x^2 - 7x + 12)$. Then, finding two numbers that multiply to 12 and add to -7, which are -3 and -4, gives the factorization $3(x - 3)(x - 4)$.

Solve - 3x2−21x+363 x ^ { 2 } - 21 x + 363x2−21x+36

Solve
- $3 x ^ { 2 } - 21 x + 36$