$$\text { If } f ( x , y ) = \frac { x ^ { \wedge } 3 + y ^ { \wedge } 3 } { x ^ { \wedge } 2 + y ^ { \wedge } 2 } , \text { calculate the value of } f ( 7.44,3.48 ) \text {. }$$
A) 6.73
B) 424.7
C) 10.92
D) None of the above

Question

Quizplus · Accepted Answer

Explanation:Given, $$f ( x , y ) = \frac { x ^ { \wedge } 3 + y ^ { \wedge } 3 } { x ^ { \wedge } 2 + y ^ { \wedge } 2 }$$Substituting the values of x and y, we get$$f ( 7.44,3.48 ) = \frac { ( 7.44 ) ^ { \wedge } 3 + ( 3.48 ) ^ { \wedge } 3 } { ( 7.44 ) ^ { \wedge } 2 + ( 3.48 ) ^ { \wedge } 2 }$$$$= \frac { 417.723392 + 39.58319488 } { 55.4496 + 12.1584 }$$$$= \frac { 457.30658688 } { 67.608 }$$$$= 6.73$$Therefore, the value of f ( 7.44,3.48 ) is 6.73.

A) 673 B) 424

A) 673
B) 424