A metal rod of length 2.0 m is moved at 6.0 m/s in a direction perpendicular to its length. A 5.0 mT magnetic field is perpendicular to both the rod and its velocity. What is the potential difference between the ends of the rod?
A) 12 mV
B) 60 mV
C) 30 mV
D) 15 mV
E) 0 mV

Question

Quizplus · Accepted Answer

The potential difference between the ends of the rod is given by the equation:

V = BLv

where B is the magnitude of the magnetic field, L is the length of the rod, and v is the velocity of the rod.

Plugging in the given values, we get:

V = (5.0 x 10^-3 T)(2.0 m)(6.0 m/s) = 60 mV

Therefore, the potential difference between the ends of the rod is 60 mV, which corresponds to choice B.

A Metal Rod of Length 2