A 20 turn coil of area 10 cm² is placed in a magnetic field so that the normal to the coil's area is in the same direction as the field. If the field has a value of 0.25 T, what is the total flux through the coil? A) 0.0 B) 5.0 × 10^-3 T·m² C) 25 × 10^-5 T·m² D) 50 T·m² E) 25 T·m²

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Quizplus · Accepted Answer

The magnetic flux ($\Phi$) through a coil is given by the formula $\Phi = NBA$, where $N$ is the number of turns in the coil, $B$ is the magnetic field strength, and $A$ is the area of the coil. Given $N = 20$, $B = 0.25$ T, and $A = 10 \times 10^{-4}$ m$^2$ (since $10$ cm$^2$ = $10 \times 10^{-4}$ m$^2$), the total flux is $\Phi = 20 \times 0.25 \times 10 \times 10^{-4} = 5.0 \times 10^{-3}$ T·m$^2$.

A 20 Turn Coil of Area 10 Cm2 Is Placed

A 20 Turn Coil of Area 10 Cm² Is Placed