$\text { Write an equation of the line that passes through the point } ( - 6,4 ) \text { and is }$ perpendicular to the line $x + y = 5$.
A) $x - y + 10 = 0$
B) $x - y + 2 = 0$
C) $x + y - 2 = 0$
D) $x + y + 10 = 0$
E) $x + y - 5 = 0$

Question

Quizplus · Accepted Answer

The slope of the line $x + y = 5$ is -1 (since it can be rewritten as $y = -x + 5$). A line perpendicular to it will have a slope of the negative reciprocal, which is 1. Using the point-slope form with the point (-6,4), the equation becomes $y - 4 = 1(x + 6)$, simplifying to $x - y + 10 = 0$.

Write an equation of the line that passes through the point (−6,4) and is \text { Write an equation of the line that passes through the point } ( - 6,4 ) \text { and is } Write an equation of the line that passes through the point (−6,4) and is

$\text { Write an equation of the line that passes through the point } ( - 6,4 ) \text { and is }$