all intercepts: $$y = x ^ { 2 } - x - 12$$
A) $x$-intercepts: $( 4,0 ) , ( - 3,0 ) ; y$-intercepts: $( 0,4 ) , ( 0,3 )$
B) $x$-intercept: $( 12,0 ) ; y$-intercepts: $( 0,4 ) , ( 0,3 )$
C) $x$-intercepts: $( 4,0 ) , ( - 3,0 ) ; y$-intercept: $( 0 , - 12 )$
D) $x$-intercepts: $( 4,0 ) , ( - 3,0 ) ; y$-intercepts: $( 0 , - 12 ) , ( 0,12 )$
E) $x$-intercept: $( - 3,0 ) ; y$-intercept: $( 0 , - 12 )$

Question

Quizplus · Accepted Answer

To find the x-intercepts, set y = 0 and solve for x: $0 = x^2 - x - 12$, which factors to $(x - 4)(x + 3) = 0$, giving x-intercepts at (4,0) and (-3,0). For the y-intercept, set x = 0: $y = 0^2 - 0 - 12 = -12$, giving a y-intercept at (0, -12).

All Intercepts y=x2−x−12y = x ^ { 2 } - x - 12y=x2−x−12

All Intercepts $y = x ^ { 2 } - x - 12$