Two solenoids are each made of 2000 turns of copper wire per meter. Solenoid I is 2 m long, while solenoid II is 1 m long. When equal currents are present in the two solenoids, the ratio of the magnetic field BI along the axis of solenoid I to the magnetic field BII along the axis of solenoid II, BI/BII, is

Question

Quizplus · Accepted Answer

The magnetic field inside a solenoid is given by B = μ₀ * n * I, where n is the number of turns per unit length and I is the current. Since both solenoids have the same number of turns per meter and carry the same current, the magnetic fields are equal, making the ratio BI/BII equal to 1.

Two Solenoids Are Each Made of 2000 Turns of Copper