Two solenoids of equal length are each made of 2000 turns of copper wire per meter. Solenoid I has a 5.00-cm radius; solenoid II a 10.0-cm radius. When equal currents are present in the two solenoids, the ratio of the magnitude of the magnetic field BI along the axis of solenoid I to the magnitude of the magnetic field BII along the axis of solenoid II, BI/BII, is

Question

Quizplus · Accepted Answer

The magnetic field inside a solenoid is given by B = μ₀ * n * I, where n is the number of turns per unit length and I is the current. Since both solenoids have the same number of turns per meter and carry the same current, the magnetic field is independent of the radius. Therefore, BI/BII = 1.

Two Solenoids of Equal Length Are Each Made of 2000