Solve $\left[ \begin{array} { l l }
2 & x \
6 & 0
\end{array} \right] \left[ \begin{array} { l l }
y & 3 \
- 2 & 2
\end{array} \right] = \left[ \begin{array} { l l }
1 & 3 \
- 6 & 18
\end{array} \right]$ for $x$ and $y$ .

Name: Solve $\left[ \begin{array} { l l } 2 & x \\ 6 & 0 \end{array} \right] \left[ \begin{array} { l l } y & 3 \\ - 2 & 2 \end{array} \right] = \left[ \begin{array} { l l } 1 & 3 \\ - 6 & 18 \end{array} \right]$ for $x$ and $y$ .
Brand: Quizplus
Rating: 4.8 (51 reviews)

Question

Solve $\left[ \begin{array} { l l } 
2 & x \
6 & 0
\end{array} \right] \left[ \begin{array} { l l } 
y & 3 \
- 2 & 2
\end{array} \right] = \left[ \begin{array} { l l } 
1 & 3 \
- 6 & 18
\end{array} \right]$  for $x$  and $y$  .

Quizplus · Accepted Answer

The Answer is

\left[ \begin{array} { l l } 2 & x \6 & 0\end{array} ight] \left[ \begin{array} { l l } y & 3 \- 2 & 2\end{array} ight] = \left[ \begin{array} { c c } 2 y - 2 x & 6 + 2 x \6 y & 18\end{array} ight]

\Rightarrow

\left[ \begin{array} { c c } 2 y - 2 x & 6 + 2 x \6 y & 18\end{array} ight] = \left[ \begin{array} { c c } 1 & 3 \- 6 & 18\end{array} ight]

\Rightarrow

\left\{ \begin{array} { l } 2 y - 2 x = 1 \6 + 2 x = 3\end{array} ight.

\Rightarrow

x = - \frac { 3 } { 2 }

,

y = - 1

Solve For xxx And yyy

Solve For $x$ And $y$