$\text { If } \mathrm { V } _ { \mathrm { bc } } = 295 \angle -115 ^ { \circ } \mathrm { V } \text {, what are } \mathrm { V } _ { \mathrm { ab } } , \mathrm { V } _ { \mathrm { ca } } \text { and } \mathrm { V } _ { \mathrm { an } } , \mathrm { V } _ { \mathrm { bn } } , \mathrm { V } _ { \mathrm { cn } } \text { for the balanced three-phase }$ sources?

Question

Quizplus · Accepted Answer

The Answer is

\begin{array} { l } \mathrm { V } _ { \mathrm { bc } } = 295 \angle - 115 ^ { \circ } \\mathrm { V } _ { \mathrm { ab } } = 295 \angle - 115 ^ { \circ } + 120 ^ { \circ } = 295 \angle 5 ^ { \circ } \mathrm { V } \\mathrm { V } _ { \mathrm { ca } } = 295 \angle - 115 ^ { \circ } - 120 ^ { \circ } = 295 \angle - 235 ^ { \circ } = 295 \angle 125 ^ { \circ } \mathrm { V } \\mathrm { V } _ { \mathrm { an } } = 295 / \sqrt { 3 } \angle - 25 ^ { \circ } = 170.3183 \angle - 25 ^ { \circ } \mathrm { V } \\mathrm { V } _ { \mathrm { bn } } = 170.3183 \angle - 145 ^ { \circ } \mathrm { V } \\mathrm { V } _ { \mathrm { cn } } = 170.3183 \angle - 265 ^ { \circ } = 170.3183 \angle 95 ^ { \circ } \mathrm { V }\end{array}

Sources