Use the quadratic formula to solve the quadratic equation.
-$x ^ { 2 } + x + 4 = 0$
A) $x = \frac { 1 \pm \sqrt { 15 } } { 2 }$
B)no real solution
C) $x = \frac { - 1 \pm \sqrt { 15 } } { 2 }$
D) $x = 1 \pm \sqrt { 15 }$

Question

Quizplus · Accepted Answer

The discriminant of the quadratic equation $x^2 + x + 4 = 0$ is $b^2 - 4ac = 1^2 - 4(1)(4) = 1 - 16 = -15$, which is negative, indicating that there are no real solutions.

Use the Quadratic Formula to Solve the Quadratic Equation x2+x+4=0x ^ { 2 } + x + 4 = 0x2+x+4=0

Use the Quadratic Formula to Solve the Quadratic Equation $x ^ { 2 } + x + 4 = 0$