Use the quadratic formula to solve the quadratic equation.
-$10 y ^ { 2 } = 13 y - 4$
A) $y = \frac { 1 } { 2 } , \frac { 5 } { 4 }$
B) $y = - \frac { 1 } { 2 } , \frac { 4 } { 5 }$
C) $y = \frac { 1 } { 2 } , \frac { 4 } { 5 }$
D) $\mathrm { y } = 2 , \frac { 4 } { 5 }$

Question

Quizplus · Accepted Answer

Rearrange the equation to $10y^2 - 13y + 4 = 0$ and apply the quadratic formula $y = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}$ with $a = 10$, $b = -13$, $c = 4$. Solving gives $y = \frac{1}{2}$ and $y = \frac{4}{5}$.

Use the Quadratic Formula to Solve the Quadratic Equation 10y2=13y−410 y ^ { 2 } = 13 y - 410y2=13y−4

Use the Quadratic Formula to Solve the Quadratic Equation $10 y ^ { 2 } = 13 y - 4$