Solve using the square root property.
-$( 2 m - 1 ) ^ { 2 } = 27$
A) $\mathrm { m } = \frac { 1 \pm 3 \sqrt { 3 } } { 2 }$
B) $\mathrm { m } = \frac { 1 + 3 \sqrt { 3 } } { 2 }$
C) $m = \frac { 1 \pm 9 \sqrt { 3 } } { 2 }$
D) $\mathrm { m } = \frac { 3 \sqrt { 3 } \pm 1 } { 2 }$

Question

Quizplus · Accepted Answer

First, take the square root of both sides to get $2m - 1 = \pm \sqrt{27}$. Simplifying $\sqrt{27}$ gives $\pm 3\sqrt{3}$. Then, solve for $m$ by adding 1 to both sides and dividing by 2, resulting in $m = \frac{1 \pm 3\sqrt{3}}{2}$.

Solve Using the Square Root Property (2m−1)2=27( 2 m - 1 ) ^ { 2 } = 27(2m−1)2=27

Solve Using the Square Root Property $( 2 m - 1 ) ^ { 2 } = 27$