Solve by the most appropriate method.
-$2 x ^ { 2 } - 7 x - 9 = 0$
A) $x = \frac { 2 } { 9 } , - 1$ 1
B)x $x = \frac { 9 } { 2 } , - 1$
C) $x = \frac { 2 } { 9 } , 1$
D) $x = \frac { 2 } { 9 } , 0$

Question

Quizplus · Accepted Answer

The quadratic equation $2x^2 - 7x - 9 = 0$ can be solved using the quadratic formula $x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}$, where $a = 2$, $b = -7$, and $c = -9$. Plugging these values into the formula gives $x = \frac{7 \pm \sqrt{(-7)^2 - 4(2)(-9)}}{2(2)}$, which simplifies to $x = \frac{7 \pm \sqrt{49 + 72}}{4}$, or $x = \frac{7 \pm \sqrt{121}}{4}$. This further simplifies to $x = \frac{7 \pm 11}{4}$, giving the solutions $x = \frac{9}{2}$ and $x = -1$.

Solve by the Most Appropriate Method 2x2−7x−9=02 x ^ { 2 } - 7 x - 9 = 02x2−7x−9=0

Solve by the Most Appropriate Method $2 x ^ { 2 } - 7 x - 9 = 0$