Solve by completing the square.
-$2 m ^ { 2 } + 12 m + 1 = 0$
A) $m = \frac { - 12 \pm \sqrt { 34 } } { 2 }$
B)m $m = \frac { - 6 \pm \sqrt { 34 } } { 4 }$
C)m $\mathrm { m } = \frac { - 6 \pm \sqrt { 38 } } { 2 }$
D) $m = \frac { - 6 \pm \sqrt { 34 } } { 2 }$

Question

Quizplus · Accepted Answer

To complete the square, divide the equation by 2: $m^2 + 6m + \frac{1}{2} = 0$. Then, add and subtract $(\frac{6}{2})^2 = 9$ inside the equation: $m^2 + 6m + 9 = \frac{1}{2} + 9$. This gives $(m + 3)^2 = \frac{19}{2}$. Solving for $m$, we get $m = -3 \pm \sqrt{\frac{19}{2}}$, which simplifies to $m = \frac{-6 \pm \sqrt{34}}{2}$.

Solve by Completing the Square 2m2+12m+1=02 m ^ { 2 } + 12 m + 1 = 02m2+12m+1=0

Solve by Completing the Square $2 m ^ { 2 } + 12 m + 1 = 0$