Solve using the quadratic formula.
-$x ^ { 2 } + 4 x + 3 = 0$
A)x = 6, -3
B)x = -1, -3
C)x = 1, -1
D)x = 1, 3

Question

Quizplus · Accepted Answer

The quadratic formula is $x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}$, where $a = 1$, $b = 4$, and $c = 3$. Plugging these values in gives $x = \frac{-4 \pm \sqrt{(4)^2 - 4(1)(3)}}{2(1)} = \frac{-4 \pm \sqrt{16 - 12}}{2} = \frac{-4 \pm \sqrt{4}}{2} = \frac{-4 \pm 2}{2}$, which results in $x = -1$ and $x = -3$.

Solve Using the Quadratic Formula x2+4x+3=0x ^ { 2 } + 4 x + 3 = 0x2+4x+3=0

Solve Using the Quadratic Formula $x ^ { 2 } + 4 x + 3 = 0$