Write out the series.
-$$\sum _ { n = 1 } ^ { 6 } ( 4 n - 3 )$$
A)45
B)1 + 5 + 9 + 13 + 17 + 21 + ...
C)1 + 1 + 5 + 9 + 13 + 17
D)1 + 5 + 9 + 13 + 17 + 21

Question

Quizplus · Accepted Answer

The series is generated by substituting values of $n$ from 1 to 6 into the formula $4n - 3$. For $n=1$, the term is $4(1) - 3 = 1$; for $n=2$, it's $4(2) - 3 = 5$, and so on up to $n=6$, which gives $4(6) - 3 = 21$. Therefore, the series is 1, 5, 9, 13, 17, 21.

Write Out the Series ∑n=16(4n−3)\sum _ { n = 1 } ^ { 6 } ( 4 n - 3 )n=1∑6​(4n−3)

Write Out the Series $\sum _ { n = 1 } ^ { 6 } ( 4 n - 3 )$