Carry the answer to two decimal places. A piece of $$\begin{aligned}
R = \frac { K L } { d ^ { 2 } } \quad \text { where } & R = \text { resistance in ohms } \
& L = \text { length in feet } \
& d = \text { diameter in mils } \
& K = 10.8 \text { (constant) }
\end{aligned}$$ -inch diameter copper rod is rolled down in a mill to 0.010 inch in thickness for magnet wire sleeving and clips. In decimal form, how much is the copper reduced in size?

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The Answer of Carry the answer to two decimal places. A piece of $$\begin{aligned}
R = \frac { K L } { d ^ { 2 } } \quad \text { where } & R = \text { resistance in ohms } \
& L = \text { length in feet } \
& d = \text { diameter in mils } \
& K = 10.8 \text { (constant) }
\end{aligned}$$ -inch diameter copper rod is rolled down in a mill to 0.010 inch in thickness for magnet wire sleeving and clips. In decimal form, how much is the copper reduced in size?

Carry the Answer to Two Decimal Places -Inch Diameter Copper Rod Is Rolled Down in a Mill