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Practical Problems in Mathematics for Electricians
Quiz 3: Decimal Fractions
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Question 21
Short Answer
Carry the answer to two decimal places. A certain type of cable weighs 500.88 pounds per one thousand feet. Determine the weight of 53 feet of this cable. Round the answer to the nearest hundredth.
Question 22
Short Answer
Carry the answer to two decimal places. What is the total cost to repair an electric outlet if the following materials and labor are required: one shallow box at $0.65, one ;
h
p
=
3
(
E
)
(
I
)
(
E
f
f
)
(
P
F
)
746
h p = \frac { \sqrt { 3 } ( E ) (I ) ( E f f ) ( P F ) } { 746 }
h
p
=
746
3
ā
(
E
)
(
I
)
(
E
ff
)
(
PF
)
ā
-inch hickey at $0.98, one flush toggle switch at $1.17, and one hour of labor at $65?
Question 23
Short Answer
Carry the answer to two decimal places. The circumference of a pulley equals the diameter multiplied by 3.1416. Find the difference in circumference between the two pulleys shown.
Question 24
Short Answer
Carry the answer to four decimal places. A shim is made 0.0025 inch thick. The thickness should be 0.00225 inch. Find the difference in the thickness.
P
=
E
2
/
R
P = E ^ { 2 } / R
P
=
E
2
/
R
Question 25
Short Answer
Carry the answer to four decimal places. If A= 0.375 inch, B=0.923 inch, C=1.0992 inches, find G
R
T
R _ { T }
R
T
ā
Question 26
Short Answer
Carry the answer to four decimal places. If D=3.1875 inches and E=0.5625 inch, find C.
Question 27
Short Answer
Carry the answer to four decimal places. What is the difference in diameters between 13 wire and number 15 wire?
Question 28
Short Answer
Carry the answer to four decimal places. The inside diameter of a motor shaft bearing is 0.0075 centimeter wider than the shaft. The shaft diameter is 4.75 centimeters. What is the inside diameter of the bearing?
Question 29
Short Answer
Carry the answer to four decimal places. If one cubic inch of copper weighs 0.314 pound, find the weight of a piece of copper that contains 2.25 cubic inches.
Question 30
Short Answer
Carry the answer to two decimal places. A piece of
R
=
K
L
d
2
Ā whereĀ
R
=
Ā resistanceĀ inĀ ohmsĀ
L
=
Ā lengthĀ inĀ feetĀ
d
=
Ā diameterĀ inĀ milsĀ
K
=
10.8
Ā (constant)Ā
\begin{aligned}R = \frac { K L } { d ^ { 2 } } \quad \text { where } & R = \text { resistance in ohms } \\& L = \text { length in feet } \\& d = \text { diameter in mils } \\& K = 10.8 \text { (constant) }\end{aligned}
R
=
d
2
K
L
ā
Ā whereĀ
ā
R
=
Ā resistanceĀ inĀ ohmsĀ
L
=
Ā lengthĀ inĀ feetĀ
d
=
Ā diameterĀ inĀ milsĀ
K
=
10.8
Ā (constant)Ā
ā
-inch diameter copper rod is rolled down in a mill to 0.010 inch in thickness for magnet wire sleeving and clips. In decimal form, how much is the copper reduced in size?
Question 31
Short Answer
Carry the answer to two decimal places. The weight of a certain wire is 145 pounds per one thousand feet. What is the cost of 600 feet of this wire at $1.40 per one hundred pounds?
Question 32
Short Answer
Carry the answer to four decimal places. How much larger is the diameter of number 11 wire than that of number 16 wire?
Ā AMERICANĀ WIREĀ GAUGEĀ
Ā SIZEĀ NUMBERĀ
Ā WIREĀ DIAMETERĀ
Ā INĀ INCHESĀ
10
0.10190
11
0.09074
12
0.08081
13
0.07196
14
0.06408
15
0.05707
16
0.05082
\begin{array}{|c|c|}\hline \begin{array}{c}\text { AMERICAN WIRE GAUGE } \\\text { SIZE NUMBER }\end{array} & \begin{array}{c}\text { WIRE DIAMETER } \\\text { IN INCHES }\end{array} \\\hline 10 & 0.10190 \\\hline 11 & 0.09074 \\\hline 12 & 0.08081 \\\hline 13 & 0.07196 \\\hline 14 & 0.06408 \\\hline 15 & 0.05707 \\\hline 16 & 0.05082 \\\hline\end{array}
Ā AMERICANĀ WIREĀ GAUGEĀ
Ā SIZEĀ NUMBERĀ
ā
10
11
12
13
14
15
16
ā
Ā WIREĀ DIAMETERĀ
Ā INĀ INCHESĀ
ā
0.10190
0.09074
0.08081
0.07196
0.06408
0.05707
0.05082
ā
ā
Question 33
Short Answer
Carry the answer to four decimal places. A special resistance wire has a diameter of 0.037 inch. The next smaller size is 0.0345 inch in diameter. Find the difference in the diameters.
Question 34
Short Answer
Carry the answer to two decimal places. An electrician receives $787.50 for a 35-hour week. What is his rate of pay per hour?
Question 35
Short Answer
Carry the answer to four decimal places. The total current in the diagram divides at point A. How much current exists at point B?
E
=
P
/
I
E = P / I
E
=
P
/
I
Question 36
Short Answer
Carry the answer to two decimal places. What is the total weight of a container of 7 gallons of liquid insulating material if one gallon weighs 9.36 pounds and the container alone weighs 6.87 pounds?
Question 37
Short Answer
Carry the answer to two decimal places. The lamps in the figure require a total current of 7.76 amperes. How many amperes will 2 lamps require? (All the lamps are of the same type, and each requires the same number of amperes.)