Divide. $\left( 12 b ^ { 3 } - 36 b ^ { 2 } - 3 b \right) \div ( - 3 b )$
A) $4 b ^ { 2 } - 12 b + 1$
B) $- 4 b ^ { 2 } + 12 b + 1$
C) $b ^ { 2 }$
D) $b + 1$
E) $b ^ { 14 } + b ^ { 13 } + b ^ { 12 }$

Question

Quizplus · Accepted Answer

Dividing each term in the polynomial by $-3b$ gives: $\frac{12b^3}{-3b} = -4b^2$, $\frac{-36b^2}{-3b} = 12b$, and $\frac{-3b}{-3b} = 1$, resulting in $-4b^2 + 12b + 1$.

Divide (12b3−36b2−3b)÷(−3b)\left( 12 b ^ { 3 } - 36 b ^ { 2 } - 3 b \right) \div ( - 3 b )(12b3−36b2−3b)÷(−3b)

Divide $\left( 12 b ^ { 3 } - 36 b ^ { 2 } - 3 b \right) \div ( - 3 b )$