Divide. $\frac { b z ^ { 4 } - b z ^ { 3 } + b z ^ { 2 } - 7 b z } { - b z }$
A) $- z ^ { 3 } + z ^ { 2 } - z + 7$
B) $- b z ^ { 3 } + b z ^ { 2 } + b z + b + 7$
C) $- z ^ { 3 } + z ^ { 2 } + z + 7$
D) $- z ^ { 3 } + z ^ { 2 } - z + 7$.
E) $- b z ^ { 3 } + b z ^ { 2 } - b z + 7$

Question

Quizplus · Accepted Answer

We can simplify the expression by factoring out a common factor of $-bz$ from the numerator:
$$\frac{bz^4-bz^3+bz^2-7bz}{-bz}=-z^3+z^2-z+7$$
Therefore, the correct answer is (D).

Divide bz4−bz3+bz2−7bz−bz\frac { b z ^ { 4 } - b z ^ { 3 } + b z ^ { 2 } - 7 b z } { - b z }−bzbz4−bz3+bz2−7bz​

Divide $\frac { b z ^ { 4 } - b z ^ { 3 } + b z ^ { 2 } - 7 b z } { - b z }$