Divide. $\frac { - 14 a ^ { 8 } b ^ { 3 } } { - 12 a ^ { 4 } b ^ { 8 } }$
A) $\frac { 7 a ^ { 12 } } { 6 b ^ { 11 } }$
B) $\frac { 7 a ^ { 4 } } { 6 b ^ { 5 } }$
C) $\frac { 6 a ^ { 4 } } { 7 b ^ { 5 } }$
D) $\frac { 7 b ^ { 5 } } { 6 a ^ { 4 } }$
E) $\frac { 6 b ^ { 5 } } { 7 a ^ { 4 } }$

Question

Quizplus · Accepted Answer

To simplify the division of two fractions, we multiply the first fraction by the reciprocal of the second fraction. In this case, we have:

\begin{align*}
\frac{-14a^8b^3}{-12a^4b^8} &= \frac{-14}{-12} \cdot \frac{a^8}{a^4} \cdot \frac{b^3}{b^8} \
&= \frac{7}{6} a^{8-4} b^{3-8} \
&= \frac{7}{6} a^4 b^{-5} \
&= \frac{7a^4}{6b^5}
\end{align*}

Therefore, the answer is B: $\frac { 7 a ^ { 4 } } { 6 b ^ { 5 } }$.

Divide −14a8b3−12a4b8\frac { - 14 a ^ { 8 } b ^ { 3 } } { - 12 a ^ { 4 } b ^ { 8 } }−12a4b8−14a8b3​

Divide $\frac { - 14 a ^ { 8 } b ^ { 3 } } { - 12 a ^ { 4 } b ^ { 8 } }$