Use the function $f ( x ) = \frac { 1 } { x }$ to find and simplify the expression for $\frac { f ( 14 + h ) - f ( 14 ) } { h }$ .
A) $- \frac { 1 } { 14 ( h + 14 ) } , h \neq 0$
B) $- \frac { 14 h } { ( h + 14 ) } , h \neq 0$
C) $- \frac { h } { 14 ( h + 14 ) } , h \neq 0$
D) $\frac { 1 } { 14 ( h + 14 ) } , h \neq 0$
E) $- \frac { 1 } { ( h + 14 ) } , h \neq 0$

Question

Quizplus · Accepted Answer

Substituting $f(14+h) = \frac{1}{14+h}$ and $f(14) = \frac{1}{14}$ into the expression and simplifying gives $-\frac{1}{14(h+14)}$, with $h \neq 0$ to avoid division by zero.

Use the Function f(x)=1xf ( x ) = \frac { 1 } { x }f(x)=x1​

Use the Function $f ( x ) = \frac { 1 } { x }$