Question 1

Find the three measures of central tendency (the mean, median, and mode). $$7,11,17,18,22$$
A) Mean: 17 Median: 15
Mode: none
B) Mean: 15 Median: 17
Mode: none
C) Mean: none Median: 17
Mode: 15
D) Mean: 15 Median: 15
Mode: 17
E) Mean: 15 Median: none
Mode: 17

Accepted Answer

The mean is calculated by adding all the numbers together and dividing by the count of numbers: $(7+11+17+18+22)/5 = 75/5 = 15$. The median is the middle number when they are listed in order, which is 17 for this set. Since there are no repeated numbers, there is no mode.

Question 2

Consider the following salaries for the executives of a certain company. $$\begin{array}{l}
\text { cellpadding="0" cellspacing="0" width } = 80 \% \text { " border="0"> }\
\begin{array} { l l } 
 { \text { Position } } & \text { Salary } \
\text { President } & \$ 220,000 \
1 \text { st VP } & \$ 140,000 \
\text { 2nd VP } & \$ 130,000 \
\text { Supervising manager } & \$ 62,000 \
\text { Accounting manager } & \$ 62,000 \
\text { Personnel manager } & \$ 62,000 \
\text { Department manager } & \$ 26,000 \
\text { Department manager } & \$ 26,000
\end{array}
\end{array}$$ What is the mode?
A) $115,600
B) $91,000
C) $26,000
D) $62000
E) $122,800

Accepted Answer

The mode is the salary that appears most frequently. In this case, the salary of $62,000 appears three times, making it the mode. Therefore, the answer is D.

Question 3

Suppose a class obtained the following scores on a test. $\text { cellpadding }=" 0 \text { " cellspacing="0" width=" } 34 \% \text { " border }=0 ">$

$\begin{array}{rl}
\text { Score } & \text { Frequency } \
90 & 4 \
80 & 2 \
70 & 6 \
60 & 7 \
50 & 1 \
40 & 1
\end{array}$
 What is the median? If necessary, round each answer to two decimal places.
A) 69.05
B) 80
C) 70
D) 65
E) 60

Accepted Answer

The median is the middle value when the data is arranged in order. There are a total of 4 + 2 + 6 + 7 + 1 + 1 = 21 scores. The median will be the 11th score when arranged in order. Since there are 7 scores of 60 and 6 scores of 70, the 11th score falls in the 70 range, making the median 70.

Question 4

Suppose a class obtained the following scores on a test. $\text { cellpadding }=" 0 " \text { cellspacing }=" 0 " \text { width }=" 34 \% \text { " border="0"> }$

$\begin{array}{ll}
\text { Score } & \text { Frequency } \
90 & 2 \
80 & 1 \
70 & 9 \
60 & 6 \
50 & 2 \
40 & 1
\end{array}$
 What is the mean? Round the answer to two decimal places as needed.
A) 66.19
B) 63.81
C) 65
D) 70
E) 3.5

Accepted Answer

To calculate the mean, multiply each score by its frequency, sum those products, and then divide by the total number of scores. The calculation is as follows: $\frac{(90*2) + (80*1) + (70*9) + (60*6) + (50*2) + (40*1)}{2+1+9+6+2+1} = \frac{180 + 80 + 630 + 360 + 100 + 40}{21} = \frac{1390}{21} = 66.19$.

Question 5

Every data set of numbers has a mean.

Accepted Answer

The mean is a measure of central tendency that represents the average of a data set. Therefore, every data set of numbers has a mean.

Question 6

Find the three measures of central tendency (the mean, median, and mode). $15,12,10,8,6,9,10$
A) Mean: 10 Median: 8
Mode: 10
B) Mean: 11 Median: 8
Mode: 10
C) Mean: 10 Median: 8
Mode: 8
D) Mean: 11 Median: 10
Mode: 10
E) Mean: 10 Median: 10
Mode: 10

Accepted Answer

The answer of Find the three measures of central tendency...

Question 7

Suppose a class obtained the following scores on a test. $$\begin{array} { l l } 
\text { cellpadding="0" cellspacing="0" width } \
\text { Score } & \text { Frequency } \
90 & 5 \
80 & 2 \
70 & 7 \
60 & 10 \
50 & 4 \
40 & 2
\end{array}$$ What is the mode?
A) 60
B) bimodal
C) 80
D) 70
E) 10

Accepted Answer

The mode is the score that appears most frequently, which is 60 with a frequency of 10.

Question 8

Suppose a class obtained the following scores on a test. $\text { cellpadding }=" 0 \text { " cellspacing }=" 0 " \text { width }=" 34 \% \text { " border="0"> }$

$\begin{array}{ll}
\text { Score } & \text { Frequency } \
90 & 1 \
80 & 5 \
70 & 6 \
60 & 8 \
50 & 1 \
40 & 2 \
30 & 1 \
0 & 1
\end{array}$ What are the mean, median, and mode? Round each answer to two decimal places as needed.
A) Mean: 52.5 Median: 70
Mode: 60
B) Mean: 52.5 Median: 70
Mode: 70
C) Mean: 62 Median: 60
Mode: 60
D) Mean: 62 Median: 70
Mode: 70
E) Mean: 52.5 Median: 60
Mode: 70

Accepted Answer

To calculate the mean, you sum all the scores and then divide by the total number of scores. The median is the middle score when all scores are arranged in order, and the mode is the score that appears most frequently. For the mean: $\frac{(90*1)+(80*5)+(70*6)+(60*8)+(50*1)+(40*2)+(30*1)+(0*1)}{25} = 1550/25 = 62$. The median, with 25 scores, is the 13th score when arranged in order, which falls in the 60 score range. The mode, the most frequent score, is 60, appearing 8 times.

Question 9

Consider G. Thumb, the leading salesperson for Moe D. Lawn Landscaping Company. Thumb turned in the following summary of clients contacted for the week of October 23-28. $$\begin{array} { c l } 
\text { cellpadding="0" cellspacing="0" width="34\%" border="0" } & \text { Number of Clients Contad } \
\text { Date } & \text { by G. Thumb } \
\text { Oct. } 23 & 14 \
\text { Oct. } 24 & 7 \
\text { Oct. } 25 & 12 \
\text { Oct. } 26 & 19 \
\text { Oct. } 27 & 12 \
\text { Oct. } 28 & 23
\end{array}$$ What are the mean, median, and mode of the number of clients per day? Round each answer to two decimal places as needed.
A) Mean: 12.5 Median: 14
Mode: 12
B) Mean: 14.5 Median: 14
Mode: 12
C) Mean: 14.5 Median: 12
Mode: 12
D) Mean: 14.5 Median: 13
Mode: 12
E) Mean: 12.5 Median: 12
Mode: 12

Accepted Answer

The answer of Consider G. Thumb, the leading salesperson for...

Question 10

The median of a set of numbers is always equal to one of the data values.

Accepted Answer

The median is the middle value of a set of data when arranged in order. It is not always equal to one of the data values. For example, the median of the set {2,4,6,8,10} is 6, which is not one of the data values.

Question 11

Consider the following salaries for the executives of a certain company. $$\begin{array}{l}
\text { cellpadding="0" cellspacing="0" width } = " 52 \% \text { " border="0"> }\
\begin{array} { l l } 
{ \text { Position } } & \text { Salary } \
\text { President } & \$ 230,000 \
\text { 1st VP } & \$ 120,000 \
\text { 2nd VP } & \$ 100,000 \
\text { Supervising manager } & \$ 52,000 \
\text { Accounting manager } & \$ 52,000 \
\text { Personnel manager } & \$ 52,000 \
\text { Department manager } & \$ 30,000 \
\text { Department manager } & \$ 30,000
\end{array}
\end{array}$$ What is the mean?
A) $110,800
B) $52,000
C) $106,400
D) $30,000
E) $83,250

Accepted Answer

The mean salary is calculated by summing all the salaries and dividing by the number of positions: (230,000 + 120,000 + 100,000 + 52,000 + 52,000 + 52,000 + 30,000 + 30,000) / 8 = $83,250.

Question 12

The salaries of employees of the Moe D. Lawn Landscaping Company are below. $\text { cellpadding }=" 0 \text { " cellspacing }=" 0 \text { " width }=" 34 \% \text { " border }=" 0 ">$
$\begin{array}{rl}
\text { Salary } & \text { Frequency } \
23,000 & 4 \
28,000 & 3 \
32,000 & 2 \
37,000 & 2
\end{array}$

What are the mean, median, and mode? Round each answer to two decimal places if needed.
A) Mean: 30,000 Median: 28,000
Mode: 23,000
B) Mean: 30,000 Median: 32,000
Mode: 23,000
C) Mean: 30,000 Median: 23,000
Mode: 28,000
D) Mean: 28,545.45 Median: 32,000
Mode: 23,000
E) Mean: 28,545.45 Median: 28,000
Mode: 23,000

Accepted Answer

The answer of The salaries of employees of the Moe...

Question 13

Suppose the 2003 prices, per ton, of wine grapes for different kinds of wine are given in the following table. $$\begin{array} { l l } 
\text { cellpadding="0" cellspacing="0" width=" } 52 \% \text { " border } \
\text { Variety } & \text { Price } \
\text { Cabernet Sauvignon } & \$ 1,800 \
\text { Merlot } & \$ 1,950 \
\text { Zinfandel } & \$ 1,550 \
\text { Pinot Noir } & \$ 1,350 \
\text { Chardonnay } & \$ 1,550 \
\text { Sauvignon Blanc } & \$ 1,200
\end{array}$$ What are the mean and median? Round your answers to the nearest cent as needed.
A) Mean: $1,566.67 Median: $1,800.00
B) Mean: $1,880.00 Median: none
C) Mean: $1,880.00 Median: $1,550.00
D) Mean: none Median: $1,550.00
E) Mean: $1,566.67 Median: $1,550.00

Accepted Answer

To find the mean, add all the prices together and divide by the number of varieties: $(1800 + 1950 + 1550 + 1350 + 1550 + 1200) / 6 = 9400 / 6 = 1566.67$. For the median, list the prices in ascending order: 1200, 1350, 1550, 1550, 1800, 1950. The median is the average of the two middle numbers, which are both 1550, so the median is also $1550.

Question 14

Every data set of numbers has a mode.

Accepted Answer

Some data sets can have no mode when all the values appear only once, meaning no number repeats.

Question 15

Find the three measures of central tendency (the mean, median, and mode). $$65,89,89,72,90$$
A) Mean: 89 Median: 81
Mode: 89
B) Mean: 81 Median: none
Mode: none
C) Mean: none Median: 89
Mode: 81
D) Mean: 81 Median: 89
Mode: 89
E) Mean: 81 Median: 81
Mode: none

Accepted Answer

Mean: (65+89+89+72+90)/5= 81
Median: Arrange the numbers in order, 65, 72, 89, 89, 90, and find the middle number, which is 89.
Mode: 89 appears twice, which is more than any other number. Therefore, mode is 89.

Question 16

Find the three measures of central tendency (the mean, median, and mode). $$2,3,3,5,7,9,14,21$$
A) Mean: 8 Median: 6
Mode: 3
B) Mean: 3 Median: 8
Mode: 6
C) Mean: 8 Median: none
Mode: none
D) Mean: 8 Median: 8
Mode: none
E) Mean: none Median: 3
Mode: 8

Accepted Answer

- Mean: Add all the numbers and divide by the total number of numbers: 
(2+3+3+5+7+9+14+21) / 8 = 8
- Median: The median is the middle value when the numbers are listed in order. Since there are 8 numbers, we need to find the average of the 4th and 5th value: 
(3 + 5) / 2 = 4
- Mode: The mode is the most frequent value in the list, which is 3.

Question 17

Consider the following salaries for the executives of a certain company. $$\begin{array}{l}
\text { cellpadding="0" cellspacing="0" width } = \text { " } 59 \% \text { " border="0"> }\
\begin{array} { l l } 
 { \text { Position } } & \text { Salary } \
\text { President } & \$ 240,000 \
\text { 1st VP } & \$ 230,000 \
\text { 2nd VP } & \$ 100,000 \
\text { Supervising manager } & \$ 65,000 \
\text { Accounting manager } & \$ 65,000 \
\text { Personnel manager } & \$ 39,000 \
\text { Department manager } & \$ 30,000 \
\text { Department manager } & \$ 30,000
\end{array}
\end{array}$$ What is the median?
A) $133,000
B) $140,000
C) $65,000
D) $30,000
E) $99,875

Accepted Answer

To find the median salary, list the salaries in ascending order and find the middle value. With an even number of salaries (8 in this case), the median is the average of the 4th and 5th salaries in the list. The 4th and 5th salaries are both $65,000, so the median salary is $65,000.

Question 18

Suppose that the 1999 monthly cost for health care for an employee and two dependents is given in the following table. $$\begin{array} { l c } 
\text { cellpadding="0" cellspacing="0" width } = " 55 \% " \text { bord } & \text { Cost } \
 { \text { Provider } } & \$ 422.35 \
\text { Maxicare } & \$ 425.45 \
\text { Cigna } & \$ 428.51 \
\text { Health Net } & \$ 431.82 \
\text { Pacific Care } & \$ 451.55 \
\text { Health Plan of the Redwoods } \$ 438.69 \
\text { Kaiser } & \$ 459.75 \
\text { Aetna U.S. Healthcare } & \$ 464.34 \
\text { Blue Shield HMO } & \$ 469.87 \
\text { Omni Healthcare } & \$ 473.61 \
\text { Lifeguard } &
\end{array}$$ What is the mean? Round answer to the nearest cent as needed.
A) $446.59
B) $438.69
C) $451.55
D) none
E) $443.59

Accepted Answer

To find the mean, we need to add up all the costs and divide by the number of providers. We can use a calculator or add up the costs manually:

$422.35 + $425.45 + $428.51 + $431.82 + $451.55 + $438.69 + $459.75 + $464.34 + $469.87 + $473.61 = $4,066.94

Now we divide by 10 (the number of providers):

$4,066.94/10 = $406.69

Rounding to the nearest cent, we get $446.59. Therefore, the best choice is A).

Question 19

Suppose a class obtained the following scores on a test. $$\begin{array} { l l } 
\text { cellpadding } = " 0 " \text { cellspacing } = " 0 " \text { width } = " 34 \% " \text { border } = " 0 \
\text { Score } & \text { Frequency } \
90 & 3 \
80 & 6 \
70 & 13 \
60 & 7 \
50 & 4
\end{array}$$ What are the mean, median, and mode? Round each answer to two decimal places as needed.
A) Mean: 69.09 Median: 70
Mode: 70
B) Mean: 69.09 Median: none
Mode: 70
C) Mean: 69.09 Median: none
Mode: none
D) Mean: 6.6 Median: 13
Mode: 13
E) Mean: 69.09 Median: 70
Mode: none

Accepted Answer

To find the mean, we use the formula: 
mean = (sum of scores) / (number of scores)

The sum of all the scores is: 
90(3) + 80(6) + 70(13) + 60(7) + 50(4) = 270 + 480 + 910 + 420 + 200 = 2280

The number of scores is: 3 + 6 + 13 + 7 + 4 = 33

So, 
mean = 2280 / 33 = 69.09

To find the median, we need to arrange the scores in order from lowest to highest: 
50, 60, 60, 60, 60, 60, 60, 70, 70, 70, 70, 70, 70, 70, 70, 80, 80, 80, 80, 80, 80, 90, 90, 90

Since there are an odd number of scores, the median is the middle score, which is 70.

To find the mode, we look for the score that occurs most frequently. In this case, 70 occurs most frequently, so the mode is 70.

Question 20

Find the three measures of central tendency (the mean, median, and mode). $7,8,9,10,11$
A) Mean: 9 Median: 9
Mode: none
B) Mean: 10 Median: 9
Mode: none
C) Mean: 9 Median: 10
Mode: 8
D) Mean: 9 Median: 9
Mode: 9
E) Mean: 9 Median: none
Mode: 9

Accepted Answer

The mean is calculated by adding all numbers and dividing by the count (7+8+9+10+11=45, 45/5=9). The median is the middle number in a sorted list, which is 9. There is no mode because all numbers appear only once.

Quiz 11: Graphs

Find the three measures of central tendency (the mean, median, and mode) . $7,11,17,18,22$

Every data set of numbers has a mean.

Find the three measures of central tendency (the mean, median, and mode) . $15,12,10,8,6,9,10$

Suppose a class obtained the following scores on a test. $\begin{array} { l l } \text { cellpadding="0" cellspacing="0" width } \\\text { Score } & \text { Frequency } \\90 & 5 \\80 & 2 \\70 & 7 \\60 & 10 \\50 & 4 \\40 & 2\end{array}$ What is the mode?

The median of a set of numbers is always equal to one of the data values.

Every data set of numbers has a mode.

Find the three measures of central tendency (the mean, median, and mode) . $65,89,89,72,90$

Find the three measures of central tendency (the mean, median, and mode) . $2,3,3,5,7,9,14,21$

Find the three measures of central tendency (the mean, median, and mode) . $7,8,9,10,11$

Quiz 11: Graphs

Find the three measures of central tendency (the mean, median, and mode) . 7,11,17,18,227,11,17,18,227,11,17,18,22

Every data set of numbers has a mean.

Find the three measures of central tendency (the mean, median, and mode) . 15,12,10,8,6,9,1015,12,10,8,6,9,1015,12,10,8,6,9,10

The median of a set of numbers is always equal to one of the data values.

Every data set of numbers has a mode.

Find the three measures of central tendency (the mean, median, and mode) . 65,89,89,72,9065,89,89,72,9065,89,89,72,90

Find the three measures of central tendency (the mean, median, and mode) . 2,3,3,5,7,9,14,212,3,3,5,7,9,14,212,3,3,5,7,9,14,21

Find the three measures of central tendency (the mean, median, and mode) . 7,8,9,10,117,8,9,10,117,8,9,10,11

Find the three measures of central tendency (the mean, median, and mode) . $7,11,17,18,22$

Find the three measures of central tendency (the mean, median, and mode) . $15,12,10,8,6,9,10$

Find the three measures of central tendency (the mean, median, and mode) . $65,89,89,72,90$

Find the three measures of central tendency (the mean, median, and mode) . $2,3,3,5,7,9,14,21$

Find the three measures of central tendency (the mean, median, and mode) . $7,8,9,10,11$