Suppose a class obtained the following scores on a test. $$\begin{array} { l l }
\text { cellpadding } = " 0 " \text { cellspacing } = " 0 " \text { width } = " 34 \% " \text { border } = " 0 \
\text { Score } & \text { Frequency } \
90 & 3 \
80 & 6 \
70 & 13 \
60 & 7 \
50 & 4
\end{array}$$ What are the mean, median, and mode? Round each answer to two decimal places as needed.
A) Mean: 69.09 Median: 70
Mode: 70
B) Mean: 69.09 Median: none
Mode: 70
C) Mean: 69.09 Median: none
Mode: none
D) Mean: 6.6 Median: 13
Mode: 13
E) Mean: 69.09 Median: 70
Mode: none

Question

Suppose a class obtained the following scores on a test. $$\begin{array} { l l } 
\text { cellpadding } = " 0 " \text { cellspacing } = " 0 " \text { width } = " 34 \% " \text { border } = " 0 \
\text { Score } & \text { Frequency } \
90 & 3 \
80 & 6 \
70 & 13 \
60 & 7 \
50 & 4
\end{array}$$ What are the mean, median, and mode? Round each answer to two decimal places as needed.
A) Mean: 69.09 Median: 70
Mode: 70
B) Mean: 69.09 Median: none
Mode: 70
C) Mean: 69.09 Median: none
Mode: none
D) Mean: 6.6 Median: 13
Mode: 13
E) Mean: 69.09 Median: 70
Mode: none

Quizplus · Accepted Answer

To find the mean, we use the formula: 
mean = (sum of scores) / (number of scores)

The sum of all the scores is: 
90(3) + 80(6) + 70(13) + 60(7) + 50(4) = 270 + 480 + 910 + 420 + 200 = 2280

The number of scores is: 3 + 6 + 13 + 7 + 4 = 33

So, 
mean = 2280 / 33 = 69.09

To find the median, we need to arrange the scores in order from lowest to highest: 
50, 60, 60, 60, 60, 60, 60, 70, 70, 70, 70, 70, 70, 70, 70, 80, 80, 80, 80, 80, 80, 90, 90, 90

Since there are an odd number of scores, the median is the middle score, which is 70.

To find the mode, we look for the score that occurs most frequently. In this case, 70 occurs most frequently, so the mode is 70.

Suppose a Class Obtained the Following Scores on a Test