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Question 16
If f(x) ={−2x+1−3≤x<−14−1<x≤5x−25<x<7f ( x ) = \left\{ \begin{array} { c c } - 2 x + 1 & - 3 \leq x < - 1 \\4 & - 1 < x \leq 5 \\x - 2 & 5 < x < 7\end{array} \right.f(x) =⎩⎨⎧−2x+14x−2−3≤x<−1−1<x≤55<x<7 , then
A) f(−3) =−5f ( - 3 ) = - 5f(−3) =−5 B) f(−1) =4f ( - 1 ) = 4f(−1) =4 C) f(5) =4f ( 5 ) = 4f(5) =4 D) f(5) =3f ( 5 ) = 3f(5) =3 E) f(7) =5f ( 7 ) = 5f(7) =5
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