If $f ( x ) = \left\{ \begin{array} { c c }
\frac { x - 1 } { x ^ { 2 } + 1 } & - 2 \leq x

Question

If $f ( x ) = \left\{ \begin{array} { c c } 
\frac { x - 1 } { x ^ { 2 } + 1 } & - 2 \leq x < 1 \
3 x & 3 \leq x < 6 \
10 - 7 x & 7 < x < 10
\end{array} \right.$ then

A) $f ( - 2 ) = 3$
B) $f ( 1 ) = 0$
C) $f ( 3 ) = 9$
D) $f ( 6 ) = 18$
E) $f ( 10 ) = 60$

Quizplus · Accepted Answer

For $f(-2)$, the function is defined as $\frac{x-1}{x^2+1}$, so $f(-2) \neq 3$. For $f(1)$, the function is not defined at $x=1$ because the piecewise function changes at $x=1$. For $f(3)$, the function is defined as $3x$, so $f(3) = 9$. For $f(6)$, the function is not defined because the piecewise function changes at $x=6$. For $f(10)$, the function is not defined at $x=10$ because the piecewise function changes before $x=10$.

If Then A) f(−2)=3f ( - 2 ) = 3f(−2)=3

If Then

A) $f ( - 2 ) = 3$