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Question 38
Let r(t) =−4ti−cos(t) j+sin(t) k\mathbf { r } ( t ) = - 4 t \mathbf { i } - \cos ( t ) \mathbf { j } + \sin ( t ) \mathbf { k }r(t) =−4ti−cos(t) j+sin(t) k Then the unit normal vector n(0) \mathbf { n } ( 0 ) n(0) is
A) −i- \mathbf { i }−i B) kC) iD) jE) −k- \mathbf { k }−k
Correct Answer:
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