Question 1

BeMe₂ rapidly polymerizes to form a linear chain of tetrahedral Be atoms. The same process does not occur for BeBu^t₂ due to steric hindrance and the shape at Be is linear. What sort of hybridization is present in each case?

Accepted Answer

BeMe₂ polymerizes to form a tetrahedral structure, indicating sp³ hybridization. BeBu^t₂ remains linear due to steric hindrance, indicating sp hybridization.

Question 2

For each of the atoms highlighted in bold, determine the type of hybridization present. -CH₃CH₂CCH

Accepted Answer

The carbon atom in bold is only bonded to two other atoms, which means it has a linear arrangement. This type of arrangement is consistent with sp hybridization, where the carbon has two sp hybrid orbitals and two unhybridized p orbitals.

Question 3

For each of the atoms highlighted in bold, determine the type of hybridization present. -C₆H₅CO₂H (benzoic acid)

Accepted Answer

The highlighted carbon atom in benzoic acid is part of the carboxyl group (COOH) and is bonded to two oxygen atoms and one carbon atom, forming a planar structure with 120-degree bond angles, indicating sp² hybridization.

Question 4

For each of the atoms highlighted in bold, determine the type of hybridization present. -CH₃CH₂OH

Accepted Answer

The highlighted carbon atom in CH₃CH₂OH is bonded to three hydrogen atoms and one carbon atom, making a total of four sigma bonds, which corresponds to sp³ hybridization.

Question 5

SF₆ is a hypervalent compound of sulfur which lies in the third period of the Periodic Table. Charge separation can be use to account for the exceptional valence of SF₆.

Accepted Answer

Charge separation can indeed account for the exceptional valence of SF₆.

Question 6

In the BeH₂ molecular orbital diagram shown below, the Be is double bonded to the H atoms.

Accepted Answer

The answer of In the BeH₂ molecular orbital diagram shown...

Question 7

In BeH₂, the 2$\sigma$_g orbital is closer in energy and properties to the atomic orbitals of _______

Accepted Answer

The answer of In BeH₂, the 2$\sigma$_g orbital is closer...

Question 8

The total number of electrons surrounding Xe in XeF₄ as predicted by VSEPR theory is 12. Valence bond theory would suggest that this arrangement would require d²sp³ hybridization.

Accepted Answer

XeF4 has 12 electrons around Xe (8 from Xe and 4 from F). VSEPR theory predicts a square planar shape, which requires d2sp3 hybridization to accommodate the electron pairs.

Question 9

One way of describing the bonding in XeF₂ which avoids hypervalency for xenon is using the 3 centre 4 electron bond. Which combination of orbitals generate a non-bonding combination for the XeF₂ molecule?

Accepted Answer

The in-phase combination of the two F p_z orbitals and the p_z orbital on the Xe results in a non-bonding combination. This is because the three orbitals have the same symmetry and can overlap to form a bonding molecular orbital.

Question 10

The bonding in B₂H₆ is best described by which of the following statements?

Accepted Answer

In B₂H₆, there are both 2-centre 2-electron bonds (between the S1 atom and the surrounding B0 and H atoms) and 3-centre 2-electron bonds (between the B1, U1, and surrounding S1 and B0 atoms). Therefore, choice B is the best description of the bonding in this molecule. Choice A includes the correct types of bonds but also includes 2-centre 2-electron bonding which is not present in this molecule. Choice C is incorrect as there are no 3-centre 4-electron bonds in this molecule. Choice D correctly identifies the presence of 3-centre 2-electron bonding, but does not account for the 2-centre 2-electron bonds.

Quiz 5: Polyatomic Molecules

BeMe₂ rapidly polymerizes to form a linear chain of tetrahedral Be atoms. The same process does not occur for BeBu^t₂ due to steric hindrance and the shape at Be is linear. What sort of hybridization is present in each case?

For each of the atoms highlighted in bold, determine the type of hybridization present. -CH₃CH₂CCH

For each of the atoms highlighted in bold, determine the type of hybridization present. -C₆H₅CO₂H (benzoic acid)

For each of the atoms highlighted in bold, determine the type of hybridization present. -CH₃CH₂OH

SF₆ is a hypervalent compound of sulfur which lies in the third period of the Periodic Table. Charge separation can be use to account for the exceptional valence of SF₆.

In the BeH₂ molecular orbital diagram shown below, the Be is double bonded to the H atoms.

In BeH₂, the 2 $\sigma$ _g orbital is closer in energy and properties to the atomic orbitals of _______

The total number of electrons surrounding Xe in XeF₄ as predicted by VSEPR theory is 12. Valence bond theory would suggest that this arrangement would require d²sp³ hybridization.

One way of describing the bonding in XeF₂ which avoids hypervalency for xenon is using the 3 centre 4 electron bond. Which combination of orbitals generate a non-bonding combination for the XeF₂ molecule?

The bonding in B₂H₆ is best described by which of the following statements?

Quiz 5: Polyatomic Molecules

BeMe2 rapidly polymerizes to form a linear chain of tetrahedral Be atoms. The same process does not occur for BeBut2 due to steric hindrance and the shape at Be is linear. What sort of hybridization is present in each case?

For each of the atoms highlighted in bold, determine the type of hybridization present. -CH3CH2CCH

For each of the atoms highlighted in bold, determine the type of hybridization present. -C6H5CO2H (benzoic acid)

For each of the atoms highlighted in bold, determine the type of hybridization present. -CH3CH2OH

SF6 is a hypervalent compound of sulfur which lies in the third period of the Periodic Table. Charge separation can be use to account for the exceptional valence of SF6.

In the BeH2 molecular orbital diagram shown below, the Be is double bonded to the H atoms.

In BeH2, the 2 σ\sigmaσ g orbital is closer in energy and properties to the atomic orbitals of _______

The total number of electrons surrounding Xe in XeF4 as predicted by VSEPR theory is 12. Valence bond theory would suggest that this arrangement would require d2sp3 hybridization.

One way of describing the bonding in XeF2 which avoids hypervalency for xenon is using the 3 centre 4 electron bond. Which combination of orbitals generate a non-bonding combination for the XeF2 molecule?

The bonding in B2H6 is best described by which of the following statements?

BeMe₂ rapidly polymerizes to form a linear chain of tetrahedral Be atoms. The same process does not occur for BeBu^t₂ due to steric hindrance and the shape at Be is linear. What sort of hybridization is present in each case?

For each of the atoms highlighted in bold, determine the type of hybridization present. -CH₃CH₂CCH

For each of the atoms highlighted in bold, determine the type of hybridization present. -C₆H₅CO₂H (benzoic acid)

For each of the atoms highlighted in bold, determine the type of hybridization present. -CH₃CH₂OH

SF₆ is a hypervalent compound of sulfur which lies in the third period of the Periodic Table. Charge separation can be use to account for the exceptional valence of SF₆.

In the BeH₂ molecular orbital diagram shown below, the Be is double bonded to the H atoms.

In BeH₂, the 2 $\sigma$ _g orbital is closer in energy and properties to the atomic orbitals of _______

The total number of electrons surrounding Xe in XeF₄ as predicted by VSEPR theory is 12. Valence bond theory would suggest that this arrangement would require d²sp³ hybridization.

One way of describing the bonding in XeF₂ which avoids hypervalency for xenon is using the 3 centre 4 electron bond. Which combination of orbitals generate a non-bonding combination for the XeF₂ molecule?

The bonding in B₂H₆ is best described by which of the following statements?