Factor completely. -12x² - 52x - 40 A) ( 12x + 8)(x - 5) B) Prime C) 4(3x - 2)(x + 5) D) 4(3x + 2)(x - 5)

Name: Factor completely. -12x 2 - 52x - 40 A) ( 12x + 8)(x - 5) B) Prime C) 4(3x - 2)(x + 5) D) 4(3x + 2)(x - 5)
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Question

Quizplus · Accepted Answer

The correct factorization of the given expression $12x^2 - 52x - 40$ is by first taking out the greatest common factor, which is 4, resulting in $4(3x^2 - 13x - 10)$. Factoring the quadratic expression inside the parentheses gives $4(3x + 2)(x - 5)$.

Factor Completely. -12x2 - 52x - 40

Factor Completely. -12x² - 52x - 40