Factor completely. -20x²y² - 9xy² - 20y² A) ( 5x - 5y)( 4x + 4y) B) y²(x - 5)( 20x + 4) C) ( 4x - 5y)( 5x + 4y) D) y²( 4x - 5)( 5x + 4)

Name: Factor completely. -20x 2 y 2 - 9xy 2 - 20y 2 A) ( 5x - 5y)( 4x + 4y) B) y 2 (x - 5)( 20x + 4) C) ( 4x - 5y)( 5x + 4y) D) y 2 ( 4x - 5)( 5x + 4)
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Question

Quizplus · Accepted Answer

The expression can be factored by first taking out the common factor $y^{12}$, resulting in $y^{12}(20x^2 - 9x - 20)$. Factoring the quadratic expression inside the parentheses gives $y^{12}(4x - 5)(5x + 4)$.

Factor Completely. -20x2y2 - 9xy2 - 20y2

Factor Completely. -20x²y² - 9xy² - 20y²