What is the solution of the initial value problem

A) $ y=-\frac{4}{3}-\frac{2}{3} $
B) $ y=-2 t+e^{-3 t} $
C) $ y=\frac{2}{3} e^{-3 t}-\frac{11}{3} $
D) $ y=-\frac{2}{3} e^{-3 t}+\frac{11}{3} $

Question

What is the solution of the initial value problem

A) $ y=-\frac{4}{3}-\frac{2}{3} $ 
B) $ y=-2 t+e^{-3 t} $ 
C) $ y=\frac{2}{3} e^{-3 t}-\frac{11}{3} $ 
D) $ y=-\frac{2}{3} e^{-3 t}+\frac{11}{3} $

Quizplus · Accepted Answer

The Answer of What is the solution of the initial value problem

A) $ y=-\frac{4}{3}-\frac{2}{3} $ 
B) $ y=-2 t+e^{-3 t} $ 
C) $ y=\frac{2}{3} e^{-3 t}-\frac{11}{3} $ 
D) $ y=-\frac{2}{3} e^{-3 t}+\frac{11}{3} $

What Is the Solution of the Initial Value Problem y=−43−23 y=-\frac{4}{3}-\frac{2}{3} y=−34​−32​