Solve
-A Person at the Top of a 600 Foot $h=-16 t^{2}+600$

Solve.
-A person at the top of a 600 foot tall building drops a yellow ball. The height of the yellow ball is given by the equation $h=-16 t^{2}+600$ where $h$ is measured in feet and $t$ is the number of seconds since the yellow ball was dropped. A second person, in the same building but on a lower floor that is 408 feet from the ground, drops a white ball 3 seconds after the yellow ball was dropped. The height of the white ball is given by the equation $h=-16(t-3) ^{2}+408$ where $h$ is measured in feet and $t$ is the number of seconds since the yellow ball was dropped. Find the time that the balls are the same distance above the ground and find this distance.

A) $2.5 \mathrm{sec} ; 500 \mathrm{ft}$
B) $4 \mathrm{sec} ; 344 \mathrm{ft}$
C) $3 \mathrm{sec} ; 456 \mathrm{ft}$
D) $3.5 \mathrm{sec} ; 404 \mathrm{ft}$