Solve. Use $\pi \approx 3.14$ when necessary.
-An airplane flying due south is 300 miles from the airport. Another airplane flying due west is 325 miles from the airport. How far apart are the two airplanes? Round to the nearest mile.
A) $97,500 \mathrm{mi}$
B) $195,364 \mathrm{mi}$
C) $625 \mathrm{mi}$
D) $442 \mathrm{mi}$

Question

Quizplus · Accepted Answer

The problem describes a right triangle where the legs are 300 miles and 325 miles long. To find the distance between the two airplanes, use the Pythagorean theorem: $a^2 + b^2 = c^2$, where $a = 300$ miles, $b = 325$ miles, and $c$ is the distance between the airplanes. Solving for $c$, we get $c = \sqrt{300^2 + 325^2} = \sqrt{90000 + 105625} = \sqrt{195625} \approx 442$ miles.

Solve Use π≈3.14\pi \approx 3.14π≈3.14 When Necessary 97,500mi97,500 \mathrm{mi}97,500mi B) 195,364mi195,364 \mathrm{mi}195,364mi C) 625mi625 \mathrm{mi}625mi

Solve Use $\pi \approx 3.14$ When Necessary $97,500 \mathrm{mi}$ B) $195,364 \mathrm{mi}$ C) $625 \mathrm{mi}$