Solve the Problem, If Possible $4 \mathrm{in}$ More Than Its Width

Solve the problem, if possible. Round your answer to the nearest tenth, when appropriate.
-The length of a rectangle is $4 \mathrm{in}$ . more than its width. If $2 \mathrm{in}$ . are taken from the length and added to the width, the figure becomes a square with an area of $192 \mathrm{in.}^{2}$ . What are the dimensions of the original figure?

A) $11.9 \mathrm{in}$ . by $15.9 \mathrm{in}$ .
B) 12.9 in. by $16.9 \mathrm{in}$ .
C) 10.9 in. by 14.9 in.
D) Cannot be determined without additional information