Solve the problem, if possible. Round your answer to the nearest tenth, when appropriate.
-A rectangular garden has an area of $12 \mathrm{ft}$ by $5 \mathrm{ft}$. A gravel path of equal width is to be built around the garden. How wide can the path be if there is enough gravel for $138 \mathrm{ft}^{2}$ ?
A) $4 \mathrm{ft}$
B) $10 \mathrm{ft}$
C) $5 \mathrm{ft}$
D) $3 \mathrm{ft}$

Question

Quizplus · Accepted Answer

The area of the garden is $12 \times 5 = 60 \mathrm{ft}^2$. The total area including the path is $60 + 138 = 198 \mathrm{ft}^2$. Let $x$ be the width of the path. The dimensions of the garden plus the path are $(12 + 2x)$ by $(5 + 2x)$. Solving $(12 + 2x)(5 + 2x) = 198$ gives $x = 3$.

Solve the Problem, If Possible 12ft12 \mathrm{ft}12ft By 5ft5 \mathrm{ft}5ft a Gravel Path of Equal Width Is to Be

Solve the Problem, If Possible $12 \mathrm{ft}$ By $5 \mathrm{ft}$ a Gravel Path of Equal Width Is to Be