The average acceleration of a moving body is given by $a_{a v g}=\frac{V_{f}-V_{1}}{t_{f}-t_{1}}$, where $V_{1}$ is the initial velocity, $V_{f}$ is the final velocity, $t_{1}$ is the initial time, and $t_{f}$ is the final time. Calculate the average acceleration, in $\mathrm{ft} / \mathrm{s}^{2}$, of a car that starts from rest when a stop watch reads $00.00 \mathrm{~s}$ and then accelerates to 55.0 $\mathrm{mi} . / \mathrm{h}$ when the watch reads $10.34 \mathrm{~s}$.

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The Answer of The average acceleration of a moving body is given by $a_{a v g}=\frac{V_{f}-V_{1}}{t_{f}-t_{1}}$, where $V_{1}$ is the initial velocity, $V_{f}$ is the final velocity, $t_{1}$ is the initial time, and $t_{f}$ is the final time. Calculate the average acceleration, in $\mathrm{ft} / \mathrm{s}^{2}$, of a car that starts from rest when a stop watch reads $00.00 \mathrm{~s}$ and then accelerates to 55.0 $\mathrm{mi} . / \mathrm{h}$ when the watch reads $10.34 \mathrm{~s}$.

The Average Acceleration of a Moving Body Is Given By a_{a