The kinetic energy of a moving object, in Joules (J), is given by the formula $K E=\frac{1}{2} m v^{2}$, where $m$ is the mass of the object and $v$ is its velocity. What is the kinetic energy of an electron traveling at $3.821 \times$ $10^{5} \mathrm{~m} / \mathrm{s}$ if the mass of an electron is $9.11 \times 10^{-31} \mathrm{~kg}$ ?

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The Answer of The kinetic energy of a moving object, in Joules (J), is given by the formula $K E=\frac{1}{2} m v^{2}$, where $m$ is the mass of the object and $v$ is its velocity. What is the kinetic energy of an electron traveling at $3.821 \times$ $10^{5} \mathrm{~m} / \mathrm{s}$ if the mass of an electron is $9.11 \times 10^{-31} \mathrm{~kg}$ ?

The Kinetic Energy of a Moving Object, in Joules (J) KE=12mv2K E=\frac{1}{2} m v^{2}KE=21​mv2

The Kinetic Energy of a Moving Object, in Joules (J) $K E=\frac{1}{2} m v^{2}$