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Solve For x:log⁡(2x+1)+log⁡(3x−5)=0.5x: \log (2 x+1)+\log (3 x-5)=0.5

Question 125

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Solve for x:log⁡(2x+1)+log⁡(3x−5)=0.5x: \log (2 x+1)+\log (3 x-5)=0.5

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