If the power input is $P_{1}$ and the power output is $P_{2}$, the number of decibels gained or lost is$G=10 \log \frac{P_{2}}{P_{1}}$(dB). If the amplifier gains $15.0 \mathrm{~dB}$ for an input of $90.0 \mathrm{~W}$, find the power output.

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The Answer of If the power input is $P_{1}$ and the power output is $P_{2}$, the number of decibels gained or lost is$G=10 \log \frac{P_{2}}{P_{1}}$(dB). If the amplifier gains $15.0 \mathrm{~dB}$ for an input of $90.0 \mathrm{~W}$, find the power output.

If the Power Input Is P1P_{1}P1​ And the Power Output Is P2P_{2}P2​

If the Power Input Is $P_{1}$ And the Power Output Is $P_{2}$