A particle undergoes an acceleration $a=2 t+8\left(\mathrm{~mm} / \mathrm{s}^{2}\right)$ and its velocity at $2 \mathrm{~s}$ is $15 \mathrm{~mm} / \mathrm{s}$.
(a) Find the relation between $v$ and $t$ for the particle.
(b) Find the velocity of the particle after $5 \mathrm{~s}$.

Question

Quizplus · Accepted Answer

The Answer is (a)

v=t^{2}+8 t-5

(b)

60 \mathrm{~mm} / \mathrm{s}

A Particle Undergoes an Acceleration a=2t+8( mm/s2)a=2 t+8\left(\mathrm{~mm} / \mathrm{s}^{2}\right)a=2t+8( mm/s2) And Its Velocity At

A Particle Undergoes an Acceleration $a=2 t+8\left(\mathrm{~mm} / \mathrm{s}^{2}\right)$ And Its Velocity At