Solve the Problem $B(x)=4700(3)^{x}$ , Where $x$ Is Time in Days $x=0$ And $x=5$

Solve the problem.
-The number of bacteria growing in an incubation culture increases with time according to $B(x) =4700(3) ^{x}$ , where $x$ is time in days. Find the number of bacteria when $x=0$ and $x=5$ .

A) $4700,70,500$
B) $4700,126,900$
C) $14,100,1,142,100$
D) $4700,1,142,100$