Solve the problem.
-The population of a particular city is increasing at a rate proportional to its size. It follows the function $\mathrm{P}(\mathrm{t})=1+\mathrm{ke}^{0.08 \mathrm{t}}$ where $\mathrm{k}$ is a constant and $\mathrm{t}$ is the time in years. If the current population is 29,000 , in how many years is the population expected to be 72,500 ?
A) 79 year(s)
B) 5 years(s)
C) 6 year(s)
D) 11 year(s)

Question

Quizplus · Accepted Answer

The Answer of Solve the problem.
-The population of a particular city is increasing at a rate proportional to its size. It follows the function $\mathrm{P}(\mathrm{t})=1+\mathrm{ke}^{0.08 \mathrm{t}}$ where $\mathrm{k}$ is a constant and $\mathrm{t}$ is the time in years. If the current population is 29,000 , in how many years is the population expected to be 72,500 ?
A) 79 year(s)
B) 5 years(s)
C) 6 year(s)
D) 11 year(s)

Solve the Problem P(t)=1+ke0.08t\mathrm{P}(\mathrm{t})=1+\mathrm{ke}^{0.08 \mathrm{t}}P(t)=1+ke0.08t Where k\mathrm{k}k Is a Constant And t\mathrm{t}t Is the Time in Years

Solve the Problem $\mathrm{P}(\mathrm{t})=1+\mathrm{ke}^{0.08 \mathrm{t}}$ Where $\mathrm{k}$ Is a Constant And $\mathrm{t}$ Is the Time in Years