Solve the equation for $c$.}
-$2 \mathrm{e}^{5 \mathrm{c}+8}=3 \mathrm{~d}$
A) $\mathrm{c}=\frac{\ln \left(\frac{3 \mathrm{~d}}{2}\right)-8}{5}$
B) $\mathrm{c}=\ln \left(\frac{3 \mathrm{~d}}{2}\right)-\frac{8}{5}$
C) $\mathrm{c}=\frac{\ln \left(\frac{2 \mathrm{~d}}{3}\right)+8}{5}$
D) $\mathrm{c}=\frac{\log \left(\frac{3 \mathrm{~d}}{2}\right)+8}{5}$

Question

Quizplus · Accepted Answer

Explanation:To solve for $c$, we can start by dividing both sides of the equation by $2$. This gives us:$$\mathrm{e}^{5 \mathrm{c}+8}=\frac{3 \mathrm{~d}}{2}$$Next, we can take the natural logarithm of both sides of the equation. This gives us:$$5 \mathrm{c}+8=\ln \left(\frac{3 \mathrm{~d}}{2}\right)$$Finally, we can solve for $c$ by subtracting $8$ from both sides of the equation and then dividing by $5$. This gives us:$$\mathrm{c}=\frac{\ln \left(\frac{3 \mathrm{~d}}{2}\right)-8}{5}$$Therefore, the correct answer is (A).

Solve the Equation For ccc } - 2e5c+8=3 d2 \mathrm{e}^{5 \mathrm{c}+8}=3 \mathrm{~d}2e5c+8=3 d A) c=ln⁡(3 d2)−85\mathrm{c}=\frac{\ln \left(\frac{3 \mathrm{~d}}{2}\right)-8}{5}c=5ln(23 d​)−8​

Solve the Equation For $c$ }
- $2 \mathrm{e}^{5 \mathrm{c}+8}=3 \mathrm{~d}$ A) $\mathrm{c}=\frac{\ln \left(\frac{3 \mathrm{~d}}{2}\right)-8}{5}$