Solve the problem.
-A certain noise measures 54 decibels. If the intensity is multiplied by 10, how many decibels will the new noise measure? Use the formula D = log (S/So) with So= $10^{-12} \mathrm{~watt} / \mathrm{m}^{2}$.
A) 54 decibels
B) 55 decibels
C) 540 decibels
D) 64 decibels

Question

Quizplus · Accepted Answer

When the intensity is multiplied by 10, the decibel level increases by 10. Therefore, 54 + 10 = 64 decibels.

Solve the Problem 10−12 watt/m210^{-12} \mathrm{~watt} / \mathrm{m}^{2}10−12 watt/m2 A) 54 Decibels B) 55 Decibels C) 540 Decibels

Solve the Problem $10^{-12} \mathrm{~watt} / \mathrm{m}^{2}$
A) 54 Decibels
B) 55 Decibels
C) 540 Decibels