Solve the problem.
-A certain noise produces 4.23 × = $10^{-5} \mathrm{~watt} / \mathrm{m}^{2}$of power. What is the decibel level of this noise (to nearest decibel)? Use the formula D = 10 log (S/So) with So = $10^{-12} \mathrm{~watt} / \mathrm{m}^{2}$.
A) 176 decibels
B) 8 decibels
C) 76 decibels
D) 66 decibels

Question

Quizplus · Accepted Answer

The decibel level D is calculated using the formula D = 10 log (S/So). Substituting S = 4.23 × 10^-5 and So = 10^-12, we get D = 10 log (4.23 × 10^7) ≈ 76 decibels.

Solve the Problem 10−5 watt/m210^{-5} \mathrm{~watt} / \mathrm{m}^{2}10−5 watt/m2 Of Power What Is the Decibel Level of This Noise (To

Solve the Problem $10^{-5} \mathrm{~watt} / \mathrm{m}^{2}$ Of Power What Is the Decibel Level of This Noise (To