A project consists of four activities with information as shown in the table.What is the overall variance of the project? $\begin{array}{|l|l|l|l|}
\hline&&&\text { Standard }\
\text { Activity } & \text { Predecessor } & \text { Length } & \begin{array}{l}
\text { Deviation }
\end{array} \
\hline \text { A } & - & 10 & 2 \
\hline \text { B } & \text { A } & 12 & 1 \
\hline \text { C } & \text { B } & 16 & 2 \
\hline \text { D } & \text { C } & 14 & 3\
\hline
\end{array}$

A)18
B)8
C)2.82
D)5.56

Question

A project consists of four activities with information as shown in the table.What is the overall variance of the project? $\begin{array}{|l|l|l|l|}
\hline&&&\text { Standard }\
 \text { Activity } & \text { Predecessor } & \text { Length } & \begin{array}{l}
\text { Deviation }
\end{array} \
\hline \text { A } & - & 10 & 2 \
\hline \text { B } & \text { A } & 12 & 1 \
\hline \text { C } & \text { B } & 16 & 2 \
\hline \text { D } & \text { C } & 14 & 3\
\hline 
\end{array}$

A)18
B)8
C)2.82
D)5.56

Quizplus · Accepted Answer

The overall variance of the project is calculated by summing the variances of all activities in the critical path. Since all activities are dependent on each other (A->B->C->D), all are in the critical path. The variance of an activity is the square of its standard deviation. Therefore, the overall variance = $2^2 + 1^2 + 2^2 + 3^2 = 4 + 1 + 4 + 9 = 18$.

A Project Consists of Four Activities with Information as Shown