Question 1

Briefly explain what information is available in a regular frequency distribution table that is not available in a grouped table.​

Accepted Answer

The answer of Briefly explain what information is available in...

Question 2

In February in New York,the daily high temperatures are typically low with only a few relatively warm days.A frequency distribution showing the daily high temperatures would probably form a negatively skewed distribution.​

Accepted Answer

A negatively skewed distribution would have more values on the high end, indicating that there are more warm days in February. However, the statement says that there are only a few relatively warm days, which implies that there are more cold days. Therefore, the distribution would likely be positively skewed, with more values on the low end.

Question 3

The scores for a very easy exam would probably form a positively skewed distribution.​

Accepted Answer

For a very easy exam, most students would likely score high, leading to a clustering of scores at the higher end of the scale and a tail stretching towards the lower scores, which is characteristic of a negatively skewed distribution.

Question 4

A score equal to the 5th percentile is one of the highest scores in the distribution.​

Accepted Answer

A score equal to the 5th percentile means that 95% of the scores in the distribution are higher than that score. Therefore, it is one of the lowest scores in the distribution, not one of the highest.

Question 5

Construct a stem and leaf display for the following scores.​30,23,58,28,35,67,27,42,46,3551,33,18,33,25,38,48,36,31,39

Accepted Answer

The answer of Construct a stem and leaf display for...

Question 6

Find each value requested for the set of scores in the following frequency distribution table. a. n $$\begin{array} { c l } \text { Score } & \mathrm { f } \ 5 & 1 \ 4 & 2 \ 3 & 3 \ 2 & 5 \ 1 & 2 \end{array}$$ b. ΣX c. ΣX²

Accepted Answer

The answer of Find each value requested for the set...

Question 7

For the distribution in the following table,the percentile rank for X = 25 is 82%.? $$\begin{array} { l r } 
\mathrm { X } & \mathrm { c } \% \
\hline 25 - 29 & 100 \% \
20 - 24 & 80 \% \
15 - 19 & 20 \% \
\hline
\end{array}$$

Accepted Answer

A percentile rank of 82% for X = 25 means that 82% of the data values in the distribution are below 25. Referring to the table, we can see that the only range of values that includes 25 is the "25-29" range, which has a cumulative percentage of 100%. This means that all data values in the distribution are below 29, and therefore 25 must be below 100% of data values. Since it is above the "20-24" range which has a cumulative percentage of 80%, but below the "25-29" range which has a cumulative percentage of 100%, it must fall between the 80th and 100th percentiles, giving it a percentile rank of 82%. Therefore, the statement is true.

Question 8

For the following scores:​
a. Construct a frequency distribution table.
b. Sketch a histogram of the frequency distribution.6, 4, 3, 5, 4, 2, 45, 4, 6, 1, 4, 5, 2

Accepted Answer

The answer of For the following scores:​
a. Construct a frequency...

Question 9

A stem and leaf display does not provide enough information to obtain a complete listing of the original set of scores.​

Accepted Answer

A stem and leaf display organizes data in a way that allows for the reconstruction of the original set of scores, as each "leaf" represents an actual data point in the context of its "stem" category.

Question 10

If a set of exam scores forms a negatively skewed distribution,it suggests that the majority of the students did not score well on the exam.​

Accepted Answer

A negatively skewed distribution means that the tail of the distribution is longer on the left side and most of the scores are concentrated on the right side of the distribution. Therefore, if a set of exam scores forms a negatively skewed distribution, it suggests that the majority of the students scored well on the exam.

Question 11

For the distribution in the following table,the percentile rank for X = 19.5 is 20%.? $$\begin{array} { l r } 
\mathrm { X } & \mathrm { c } \% \
\hline 25 - 29 & 100 \% \
20 - 24 & 80 \% \
15 - 19 & 20 \% \
\hline
\end{array}$$

Accepted Answer

To find the percentile rank for X = 19.5, we look at the row that contains the range 15-19. This row represents the 20th percentile of the distribution. Since 19.5 falls within this range, it must have a percentile rank of 20%. Therefore, the statement is true.

Question 12

The normal distribution is an example of a symmetrical distribution.

Accepted Answer

The normal distribution is symmetrical, meaning that its probability density function has an equal chance of producing a value either side of its mean.

Question 13

For the distribution in the following table,the 80th percentile is X = 24.? $$\begin{array} { l r } 
X & c \% \
\hline 25 - 29 & 100 \% \
20 - 24 & 80 \% \
15 - 19 & 20 \% \
\hline
\end{array}$$

Accepted Answer

The 80th percentile falls in the 20 - 24 range, but it does not specify that X = 24 exactly; it only indicates that X is within this range.

Question 14

For the distribution in the following table,the 90th percentile is X = 27.5.? $$\begin{array} { l r } 
\mathrm { X } & \mathrm { c } \% \
\hline 25 - 29 & 100 \% \
20 - 24 & 80 \% \
15 - 19 & 20 \%
\end{array}$$

Accepted Answer

The 90th percentile is within the 25-29 range, but it is not exactly 27.5. Percentiles are not necessarily the midpoint of a range.

Quiz 2: Frequency Distributions

Briefly explain what information is available in a regular frequency distribution table that is not available in a grouped table.

In February in New York,the daily high temperatures are typically low with only a few relatively warm days.A frequency distribution showing the daily high temperatures would probably form a negatively skewed distribution.

The scores for a very easy exam would probably form a positively skewed distribution.

A score equal to the 5th percentile is one of the highest scores in the distribution.

Construct a stem and leaf display for the following scores.30,23,58,28,35,67,27,42,46,3551,33,18,33,25,38,48,36,31,39

Find each value requested for the set of scores in the following frequency distribution table. a. n $\begin{array} { c l } \text { Score } & \mathrm { f } \\5 & 1 \\4 & 2 \\3 & 3 \\2 & 5 \\1 & 2\end{array}$ b. ΣX c. ΣX²

For the distribution in the following table,the percentile rank for X = 25 is 82%.? $\begin{array} { l r } \mathrm { X } & \mathrm { c } \% \\\hline 25 - 29 & 100 \% \\20 - 24 & 80 \% \\15 - 19 & 20 \% \\\hline\end{array}$

For the following scores: a. Construct a frequency distribution table. b. Sketch a histogram of the frequency distribution.6, 4, 3, 5, 4, 2, 45, 4, 6, 1, 4, 5, 2

A stem and leaf display does not provide enough information to obtain a complete listing of the original set of scores.

If a set of exam scores forms a negatively skewed distribution,it suggests that the majority of the students did not score well on the exam.

For the distribution in the following table,the percentile rank for X = 19.5 is 20%.? $\begin{array} { l r } \mathrm { X } & \mathrm { c } \% \\\hline 25 - 29 & 100 \% \\20 - 24 & 80 \% \\15 - 19 & 20 \% \\\hline\end{array}$

The normal distribution is an example of a symmetrical distribution.

For the distribution in the following table,the 80th percentile is X = 24.? $\begin{array} { l r } X & c \% \\\hline 25 - 29 & 100 \% \\20 - 24 & 80 \% \\15 - 19 & 20 \% \\\hline\end{array}$

For the distribution in the following table,the 90th percentile is X = 27.5.? $\begin{array} { l r } \mathrm { X } & \mathrm { c } \% \\\hline 25 - 29 & 100 \% \\20 - 24 & 80 \% \\15 - 19 & 20 \%\end{array}$

Quiz 2: Frequency Distributions

Briefly explain what information is available in a regular frequency distribution table that is not available in a grouped table.​

In February in New York,the daily high temperatures are typically low with only a few relatively warm days.A frequency distribution showing the daily high temperatures would probably form a negatively skewed distribution.​

The scores for a very easy exam would probably form a positively skewed distribution.​

A score equal to the 5th percentile is one of the highest scores in the distribution.​

Construct a stem and leaf display for the following scores.​30,23,58,28,35,67,27,42,46,3551,33,18,33,25,38,48,36,31,39

Find each value requested for the set of scores in the following frequency distribution table. a. n Score f5142332512\begin{array} { c l } \text { Score } & \mathrm { f } \\5 & 1 \\4 & 2 \\3 & 3 \\2 & 5 \\1 & 2\end{array} Score 54321​f12352​ b. ΣX c. ΣX2

For the distribution in the following table,the percentile rank for X = 25 is 82%.? Xc%25−29100%20−2480%15−1920%\begin{array} { l r } \mathrm { X } & \mathrm { c } \% \\\hline 25 - 29 & 100 \% \\20 - 24 & 80 \% \\15 - 19 & 20 \% \\\hline\end{array}X25−2920−2415−19​c%100%80%20%​​

For the following scores:​ a. Construct a frequency distribution table. b. Sketch a histogram of the frequency distribution.6, 4, 3, 5, 4, 2, 45, 4, 6, 1, 4, 5, 2

A stem and leaf display does not provide enough information to obtain a complete listing of the original set of scores.​

If a set of exam scores forms a negatively skewed distribution,it suggests that the majority of the students did not score well on the exam.​

For the distribution in the following table,the percentile rank for X = 19.5 is 20%.? Xc%25−29100%20−2480%15−1920%\begin{array} { l r } \mathrm { X } & \mathrm { c } \% \\\hline 25 - 29 & 100 \% \\20 - 24 & 80 \% \\15 - 19 & 20 \% \\\hline\end{array}X25−2920−2415−19​c%100%80%20%​​

The normal distribution is an example of a symmetrical distribution.

For the distribution in the following table,the 80th percentile is X = 24.? Xc%25−29100%20−2480%15−1920%\begin{array} { l r } X & c \% \\\hline 25 - 29 & 100 \% \\20 - 24 & 80 \% \\15 - 19 & 20 \% \\\hline\end{array}X25−2920−2415−19​c%100%80%20%​​

For the distribution in the following table,the 90th percentile is X = 27.5.? Xc%25−29100%20−2480%15−1920%\begin{array} { l r } \mathrm { X } & \mathrm { c } \% \\\hline 25 - 29 & 100 \% \\20 - 24 & 80 \% \\15 - 19 & 20 \%\end{array}X25−2920−2415−19​c%100%80%20%​​

Briefly explain what information is available in a regular frequency distribution table that is not available in a grouped table.

In February in New York,the daily high temperatures are typically low with only a few relatively warm days.A frequency distribution showing the daily high temperatures would probably form a negatively skewed distribution.

The scores for a very easy exam would probably form a positively skewed distribution.

A score equal to the 5th percentile is one of the highest scores in the distribution.

Construct a stem and leaf display for the following scores.30,23,58,28,35,67,27,42,46,3551,33,18,33,25,38,48,36,31,39

Find each value requested for the set of scores in the following frequency distribution table. a. n $\begin{array} { c l } \text { Score } & \mathrm { f } \\5 & 1 \\4 & 2 \\3 & 3 \\2 & 5 \\1 & 2\end{array}$ b. ΣX c. ΣX²

For the distribution in the following table,the percentile rank for X = 25 is 82%.? $\begin{array} { l r } \mathrm { X } & \mathrm { c } \% \\\hline 25 - 29 & 100 \% \\20 - 24 & 80 \% \\15 - 19 & 20 \% \\\hline\end{array}$

For the following scores: a. Construct a frequency distribution table. b. Sketch a histogram of the frequency distribution.6, 4, 3, 5, 4, 2, 45, 4, 6, 1, 4, 5, 2

A stem and leaf display does not provide enough information to obtain a complete listing of the original set of scores.

If a set of exam scores forms a negatively skewed distribution,it suggests that the majority of the students did not score well on the exam.

For the distribution in the following table,the percentile rank for X = 19.5 is 20%.? $\begin{array} { l r } \mathrm { X } & \mathrm { c } \% \\\hline 25 - 29 & 100 \% \\20 - 24 & 80 \% \\15 - 19 & 20 \% \\\hline\end{array}$

For the distribution in the following table,the 80th percentile is X = 24.? $\begin{array} { l r } X & c \% \\\hline 25 - 29 & 100 \% \\20 - 24 & 80 \% \\15 - 19 & 20 \% \\\hline\end{array}$

For the distribution in the following table,the 90th percentile is X = 27.5.? $\begin{array} { l r } \mathrm { X } & \mathrm { c } \% \\\hline 25 - 29 & 100 \% \\20 - 24 & 80 \% \\15 - 19 & 20 \%\end{array}$